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- Question 1 to 26
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- underset is equal to 266C(0)+^(26)C(1)+^(26)C(2)+(1)+..........+^(26)C...
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- The above question 26, the normal force acting, betweent :
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- 1, 2, 5, 26, ?
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- ""^(26)C(0)+""^(26)C(1)+""^(26)C(2)+…..+""^(26)C(13) is equal to :
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- Find (26)^((1)/3)).
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- In Question 26, for VCE=0 the above graph lines will be
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- If A={:[(3,2),(0,1)]:}" then:(A^(-1))^(3)=...a)(1)/(27)[(1,-26),(0,27)...
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- Discussion ppt. question 1 to 26
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