Insertion of Dielectric||Effect of Dielectric on Potential||Electric Field||Capacitance||Charge

Insertion Of Dielectric Between Plates

A dielectric is inserted between the plates of an isolated fully-charged capacitor. The dielectric completely fills the space between the plates. The magnitude of electrostatic force on either metal plate decreases, as it was before the insertion of dielectric medium. Due to insertion of dielectric slab in an isolated parallel plate capacitor (the dielectric completely fills the space between the plates), the electrostatic potential energy of the capacitor decreases.

The parallel plate of a capacitor have an area 0.2 m^(2) and are 10^(-2) m apart. The original potential difference between them is 3000V, and it decreases to 1000 when a sheet of dielectric is inserted between the plates. Compute (a) Original capacitance C_(0) (b) The original charge Q on each plate . (C) Capacitance C after insertion of the dielectric . (d) Dielectric constant K . (e) The original field E_(0) between the plates and . (f) The electric field E_(0) between the plates and . (f) The electric field E after insertion of the dielectric . (epsi_(0) = 8.85 xx 10^(-12) S.I unit).

Dielectric||Capacitance with Dielectric||Dielectric with Battery and Without Battery

calculate the effective capacitance of the connection if a dielectric material of dielectric constant K is filled in between the plates as shown in the adjoining figure (n).