Friction Between Two Blocks

A block of mass m is placed on another block of mass M which itself is lying on a horizontal surface .The coefficient of friction between two blocks is mu_(1) and that between the block of mass M and horizontal surfece is mu_(2) What maximum horizontal force can be applied to the lower block move without separation?

A block of mass m is kept over another block of mass 2m. Coefficient of friction between two blocks is mu and that of between lower blood from the horizontal surface is zero. A horizontal force F=4/3 mu mg is applied on the block of mass 2m . Acceleration of lower block is

Block A of mass 3 kg is placed on another block B of mass 5 kg placed on the smooth surface. If coefficient of friction between two blocks is 1/2 and 32 N force is applied on block B as shown in the figure, then the work done by the frictional force on block A in first two second will be (initial velocity of the system is zero and g = 10 m/s^2 )

coefficient of friction between two blocks shown in figure is mu =0.6 . The blocks are given velocities in the direction shown in figure. Find (a) the time when relative motion between them is slopped. (b) the common velocity of the two blocks. (c) the displocement of 1kg and 2kg blocks upto that instant. (Take g =10m//s^(2))

The block of mass M and are arrenged as the situation in fig is shown.The coefficient of friction between two block is mu and that between the bigger block and the ground is mu find the acceleration of the block

Block A of mass 5kg is placed on long block B having a mass of 5kg . The coefficient of friction between two block is 0.4 . There is no friction between the ground and lower block. The upper block is given a sudden velocity of 10m//s . The upper block slides toward right, so friction force acting on it will be toward left. Its reaction wall act on the lower block, which will act forward . The friction force absorbs x mechanical energy from upper block but supply only y mechanical energy to lower block. Due to friction the velocity of upper block reduces and velocity of lower block increases. This will continue till velocity of both the block get equal. The net energy loss due to friction in the entire process is

Block A of mass 5kg is placed on long block B having a mass of 5kg . The coefficient of friction between two block is 0.4 . There is no friction between the ground and lower block. The upper block is given a sudden velocity of 10m//s . The upper block slides toward right, so friction force acting on it will be toward left. Its reaction wall act on the lower block, which will act forward . The friction force absorbs x mechanical energy from upper block but supply only y mechanical energy to lower block. Due to friction the velocity of upper block reduces and velocity of lower block increases. This will continue till velocity of both the block get equal. Which curve shows the correct variation of velocity of each block v//s time?

Coefficient of friction between two block shown in figure ia mu = 0.4 . The blocks are given velocities of 2 m//s and 8 m//s in the directions figure. Find (a) The time when relative motion between them will stop (b) the common velocities of blocks upto that instant. (c) Displacement of 1 kg and 2 kg block upto that instant (g = 10 m//s^(2)) .

Two blocks A and B each of mass m are placed on a smooth horizontal surface. Two horizontal force F and 2F are applied on blocks A and B, respectively, as shown in fig. Block A does not slide on block B. Then then the normal reaction acting between the two blocks is (assume no friction between the blocks)