Pure Rolling on inclined Plane

Pure Rolling on incline Plane

A solid cylinder of mass 2kg rolls down (pure rolling) an inclined plane from a height of 4m. Its rotational kinetic energy, when its reaches the foot of the plane is (Take g=10m s^(-2))

A sphere of radius 1cm moving with 1 m/s starts going up the plane performing pure rolling on an inclined plane of inclination 30 degrees. Find total time taken by it to go up and come down the plane

A solid ball of mass 'm' is released on a rough fixed inclined plane from height H . The ball will perform pure rolling on the inclined plane. Then

An uniform spherical shell of mass m and radius R starts from rest with pure rolling on long inclined plane as shown in figure. The angular momentum of shell about point of contact after 1 s of its starting is KmR. Determine the value of k(g=10m//s^(2)) .

Calculate the acceleration of a hollow cylinder rolling down an inclined plane of inclination 30.

A ring is rolling on an inclined plane. The ratio of the linear and rotational kinetic energies will be

A body is rolling down an inclined plane. Its acceleration will not depend on the following: