Soluton of the kdifferential equaiton `(x+y)dy=a^(2) dx` is

what is the solution of the differential equaiton x dy-ydx = xy^(2) dx ?

If y = f(x) is the solution of the differential equaiton e^(3y) ((dy)/(dx) - 1) = e^(2x) and y(0) = 0 then y(x) = log (Ae^(3x) - Be^(2x))^((1)/(3)) where the value of (A + B) is:

The solution of the differential equaiton (dy)/(dx)=(1+y^(2))/(1+x^(2)) , is

The general solution of the differential equaiton (1+y^(2))dx+(1+x^(2))dy=0 , is

what is the solution of the differential equaiton 3e^(x) tan y dx + (1+e^(x)) sec^(2) y dy =0 ?

The solution of the differential equation x dx + y dy+ (x dy - y dx)/(x^(2)+y^(2))=0 is

Solution of the differential equation (x+y(dy)/(dx))/(y-x(dy)/(dx))=(x sin^(2)(x^(2)+y^(2)))/(y^(3))

Solution of differential equation y-x(dy)/(dx)=y^(2)+(dy)/(dx), when x=1,y=2, is

Intergrating factor of the differential equaiton (x^(2)+1)(dy)/(dx)+2xy=x^(2)-1 is