The phase difference between two SHM `y_(1) = 10 sin (10 pi t + (pi)/(3))` and `y_(2) = 12 sin (8 pi t + (pi)/(4))` at `t = 0.5s` is

The phase difference between two SHM y_(1) = 10 sin (10 pi t + (pi)/(3)) and y_(2) = 12 sin (8 pi t + (pi)/(4)) to t = 0.5s is

Determine the resultant of two waves given by y_(1) = 4 sin(200 pi t) and y_(2) = 3 sin(200 pi t + pi//2) .

Two simple harmonic motion, are represented by the equations y _(1) = 10 sin ( 3 pi t + (pi)/(3)) y _(2) = 5 ( sin 3 pi t + sqrt3 cos 3 pi t ) Ratio of amplitude of y _(1) to y _(2) = x :1. The value of x is __________

Two simple harmonic motions are represented by the equations y_(1) = 10 sin (3pit + (pi)/(4)) and y_(2) = 5 (3 sin 3 pi t+sqrt(3) cos 3 pi t) . Their amplitudes are in the ratio of

The equations of two SH M's are X_(1) = 4 sin (omega t + pi//2) . X_(2) = 3 sin(omega t + pi)

Two S.H.Ms are given by y_(1) = a sin ((pi)/(2) t + (pi)/(2)) and y_(2) = b sin ((2pi)/(3) t + (pi)/(2)) . The phase difference between these after 1 second is

The equation of displacement of two waves are given as y_(1) = 10 sin( 3 pi t + (pi)/(3)) , y_(2) = 5 [ sin 3 pi t + sqrt(3) cos 3 pi t] Then what is the ratio of their amplitudes

The path difference between the two waves y_(1)=a_(1) sin(omega t-(2pi x)/(lambda)) and y(2)=a_(2) cos(omega t-(2pi x)/(lambda)+phi) is

The equation of displacement of two waves are given as y_(1)=10sin(3 pi t+(pi)/(3)) , y_(2)=10sin(3 pi t+(pi)/(3)) .Then what is the ratio of their amplitudes

If two SHMs are repersented by y_(1) = 10 sin (4 pi + pi//2) and y_(2) = 5 (sin 2 pi t +sqrt 8 cos 2 pi t) , compare their amplitudes .