`5.7bar(32) + 8.bar(613)`

The value of 0.bar(3) + 0.bar(6) + 0. bar( 7 ) + 0. bar( 8 ) in fraction will be

The difference of 5.bar(76) and 2.bar(3) is

Express each of the following decimals in the form (p)/(q) , where p,q are integers and q ne 0 . (i) 0.bar(2) (ii) 0.bar(53) (iii) 2.bar(93) (iv) 18.bar(48) (v) 0.bar(235) (vi) 0.00bar(32) (vii) 1.3bar(23) (viii) 0.3bar(178) (ix) 32.12bar(35) (x) 0.40bar(7)

Express each of the following recurring decimals into the rational number : (i)0.bar(5)" "(ii)2.bar(4)" "(iii)1.bar(12)" "(iv)2.7bar(39)" "(v)0.bar(516)" "(vi)3.7bar(148)

Express each of the following recurring decimals into the rational number : (i)0.bar(32)" "(ii)0.bar(56)" "(iii)3.bar(18)" "(iv)10.bar(13)

If |bar(a)| = 2, |bar(b)| = 5, and bar(a).bar(b) = 8 then |bar(a) - bar(b)| =__________

The value of 0.bar2 + 0.bar3 + 0.bar(32) is :

The sum of 0.bar(6) and 0.bar(7) is

Express each of the following recurring decimals into the rational number : (i)0.bar(7)" "(ii)0.bar(6)" "(iii)1.bar(3)" "(iv)3.bar(8)