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If n! - n = n, then the value of n is :...

If `n! - n = n`, then the value of n is :

A

4

B

5

C

6

D

3

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The correct Answer is:
To solve the equation \( n! - n = n \), we can simplify it step by step. ### Step 1: Rewrite the equation We start with the equation: \[ n! - n = n \] We can rearrange it to: \[ n! = n + n \] This simplifies to: \[ n! = 2n \] ### Step 2: Test the values of \( n \) We will test the given options one by one to find the value of \( n \). #### Option 1: \( n = 4 \) Calculate \( 4! \): \[ 4! = 4 \times 3 \times 2 \times 1 = 24 \] Now check if \( 4! = 2 \times 4 \): \[ 24 \neq 8 \quad \text{(Not a solution)} \] #### Option 2: \( n = 5 \) Calculate \( 5! \): \[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \] Now check if \( 5! = 2 \times 5 \): \[ 120 \neq 10 \quad \text{(Not a solution)} \] #### Option 3: \( n = 6 \) Calculate \( 6! \): \[ 6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720 \] Now check if \( 6! = 2 \times 6 \): \[ 720 \neq 12 \quad \text{(Not a solution)} \] #### Option 4: \( n = 3 \) Calculate \( 3! \): \[ 3! = 3 \times 2 \times 1 = 6 \] Now check if \( 3! = 2 \times 3 \): \[ 6 = 6 \quad \text{(This is a solution)} \] ### Conclusion The value of \( n \) that satisfies the equation \( n! - n = n \) is: \[ \boxed{3} \]

To solve the equation \( n! - n = n \), we can simplify it step by step. ### Step 1: Rewrite the equation We start with the equation: \[ n! - n = n \] We can rearrange it to: ...
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QUANTUM CAT-NUMBER SYSTEM-QUESTION BANK
  1. If P + P! = P^3 , then the value of P is :

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  2. If P + P! = P^2 then the value of P is:

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  3. If n! - n = n, then the value of n is :

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  4. The appropriate value of P for the relation (P! + 1) = (P + 1)^2 is :

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  5. The value of 8! div 5! is :

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  6. If n! = ((n + 4)!)/((n + 1)!) , then the value of n is :

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  7. The value of (1.2.3…..9).(11.12.13…19).(21.22.23….29).(31.32.33……39)...

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  8. The expression 1! + 2! + 3! + 4! + ……….. + n! (where n ge 5) is not a/...

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  9. The HCF and LCM of 13! and 31! are respectively :

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  10. Find the number of zeros in the product of 10!.

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  11. Find the number of zeros at the end of the product of 2^222xx5^555

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  12. Find the number of zeros st the end of the product of the expression ...

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  13. Find the number of Zeros at the end of the expression - 10 + 100 + ...

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  14. Find the no. of zeros in expression 10 xx 100xx1000xx10000xx...1000000...

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  15. Number of zeros at the end of the following expression (5!)^(5!) + (10...

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  16. Find the largest power of 5 contained in 124! .

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  17. Find the largest power of 2 that can divide 268!.

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  18. Find the largest power of 7 that can exactly divide 777!.

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  19. Find the largest value of n in the 10^(n) which can exactly divide 100...

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  20. Find the number of zeros at the end of 1000!.

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