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(a + 1)(b-1) = 625, (a != b) in I^(+) t...

`(a + 1)(b-1) = 625, (a != b) in I^(+)` then the value of `(a +b)` is

A

`a+b ge 25`

B

`a+bge50`

C

a+b=24

D

a+b = 26

Text Solution

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The correct Answer is:
B
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