In the examination of CBSE, a candidate must get `2/5th` marks to pass, out of total marks. Vinod appeared in the same exam and get 210 marks and still failed it by 40 marks. The maximum marks which a candidate can get is :

Options

A. 500
B. 625
C. 390
D. can't be determined

Answer

To find the maximum marks a candidate can get in the CBSE examination based on the information provided, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Problem**:
We know that Vinod scored 210 marks but failed by 40 marks. This means he needed 40 more marks to pass.

2. **Calculate the Passing Marks**:
To find out how many marks Vinod needed to pass, we can add the marks he scored (210) to the marks he was short by (40):
\[ \text{Marks needed to pass} = 210 + 40 = 250 \]

3. **Setting Up the Equation**:
According to the problem, a candidate must get \( \frac{2}{5} \) of the total marks (let's denote the total marks as \( X \)) to pass. Therefore, we can set up the equation:
\[ \frac{2}{5}X = 250 \]

4. **Solving for Total Marks \( X \)**:
To find \( X \), we can multiply both sides of the equation by \( 5 \) to eliminate the fraction:
\[ 2X = 250 \times 5 \]
\[ 2X = 1250 \]
Now, divide both sides by \( 2 \):
\[ X = \frac{1250}{2} = 625 \]

5. **Conclusion**:
The maximum marks which a candidate can get is \( 625 \).

### Final Answer:
The maximum marks which a candidate can get is **625**.