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The value of (1-1/2)(1-1/3)(1-1/4)(1-1/5...

The value of `(1-1/2)(1-1/3)(1-1/4)(1-1/5)…(1-1/n) is :

A

1

B

`(1-1/n)^5`

C

`1/n`

D

can't be determined

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AI Generated Solution

The correct Answer is:
To solve the expression \((1 - \frac{1}{2})(1 - \frac{1}{3})(1 - \frac{1}{4})(1 - \frac{1}{5}) \ldots (1 - \frac{1}{n})\), let's break it down step by step. ### Step 1: Simplify Each Term We will simplify each term in the product: - For \(1 - \frac{1}{2}\): \[ 1 - \frac{1}{2} = \frac{1}{2} \] - For \(1 - \frac{1}{3}\): \[ 1 - \frac{1}{3} = \frac{2}{3} \] - For \(1 - \frac{1}{4}\): \[ 1 - \frac{1}{4} = \frac{3}{4} \] - For \(1 - \frac{1}{5}\): \[ 1 - \frac{1}{5} = \frac{4}{5} \] - Continuing this pattern, for \(1 - \frac{1}{n}\): \[ 1 - \frac{1}{n} = \frac{n-1}{n} \] ### Step 2: Write the Complete Product Now, we can write the complete product: \[ (1 - \frac{1}{2})(1 - \frac{1}{3})(1 - \frac{1}{4}) \ldots (1 - \frac{1}{n}) = \frac{1}{2} \cdot \frac{2}{3} \cdot \frac{3}{4} \cdot \frac{4}{5} \cdots \frac{n-1}{n} \] ### Step 3: Observe the Pattern Notice that in the product, most terms will cancel out: - The numerator of each fraction cancels with the denominator of the next fraction. ### Step 4: Write the Canceled Form After cancellation, we are left with: \[ \frac{1}{n} \] ### Final Answer Thus, the value of the expression \((1 - \frac{1}{2})(1 - \frac{1}{3})(1 - \frac{1}{4}) \ldots (1 - \frac{1}{n})\) is: \[ \frac{1}{n} \]
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