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A string of length, 221 metre is cut int...

A string of length, 221 metre is cut into two parts such that one part is `9/4th` as long as the rest of the string, then the difference between the larger piece the shorter piece is

A

58 m

B

53 m

C

85 m

D

none of these

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The correct Answer is:
To solve the problem, we need to find the lengths of the two parts of the string and then determine the difference between them. Let's break it down step by step. ### Step 1: Define the lengths of the two parts Let the length of the shorter part of the string be \( x \) meters. According to the problem, the longer part is \( \frac{9}{4} \) times as long as the shorter part. Therefore, the length of the longer part can be expressed as: \[ \text{Length of longer part} = \frac{9}{4}x \] ### Step 2: Set up the equation The total length of the string is given as 221 meters. Therefore, we can set up the following equation: \[ x + \frac{9}{4}x = 221 \] ### Step 3: Combine like terms To combine the terms on the left side, we need a common denominator. The term \( x \) can be rewritten as \( \frac{4}{4}x \): \[ \frac{4}{4}x + \frac{9}{4}x = 221 \] This simplifies to: \[ \frac{4x + 9x}{4} = 221 \] \[ \frac{13x}{4} = 221 \] ### Step 4: Solve for \( x \) To eliminate the fraction, multiply both sides of the equation by 4: \[ 13x = 221 \times 4 \] Calculating the right side: \[ 13x = 884 \] Now, divide both sides by 13 to find \( x \): \[ x = \frac{884}{13} \] Calculating this gives: \[ x = 68 \] ### Step 5: Find the lengths of both parts Now that we have \( x \), we can find the lengths of both parts: - Shorter part: \( x = 68 \) meters - Longer part: \( \frac{9}{4}x = \frac{9}{4} \times 68 = 153 \) meters ### Step 6: Calculate the difference between the two parts The difference between the longer part and the shorter part is: \[ \text{Difference} = 153 - 68 = 85 \text{ meters} \] ### Final Answer The difference between the larger piece and the shorter piece is **85 meters**. ---
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