`2^(73)-2^(72)-2^(71)` is same as :

Options

A. `2^(72)`
B. `2^(71)`
C. `2^(70)`
D. none of these

Answer

To solve the expression \(2^{73} - 2^{72} - 2^{71}\), we can follow these steps:

### Step 1: Factor out the common term
We notice that all the terms in the expression share a common factor of \(2^{71}\). So, we can factor \(2^{71}\) out of the expression.

\[ 2^{73} - 2^{72} - 2^{71} = 2^{71}(2^{2} - 2^{1} - 1) \]

### Step 2: Simplify the expression inside the parentheses
Now we simplify the expression inside the parentheses:

\[ 2^{2} - 2^{1} - 1 = 4 - 2 - 1 \]

Calculating this gives:

\[ 4 - 2 - 1 = 1 \]

### Step 3: Substitute back into the factored expression
Now we substitute back into our factored expression:

\[ 2^{71}(1) = 2^{71} \]

### Conclusion
Thus, the original expression \(2^{73} - 2^{72} - 2^{71}\) simplifies to:

\[ 2^{71} \]

### Final Answer
The answer is \(2^{71}\).

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