Anjuli has written all the letters (or characters) of English alphabets horizontally in a single line. She started counting as `A-1,B-2 . . . .Z-26` and reversed back as `Y-27 , X-28 , W-29 . . . A-51` and further reversed back as `B-52 , C-53 , . . . ` etc . She continued will she reached 777th character . At which letter or character she stopped counting ?

Options

A. Y
B. B
C. R
D. none of these

Answer

To solve the problem step by step, we will follow the counting pattern described in the question.

### Step 1: Understand the counting pattern
Anjuli counts the letters of the English alphabet as follows:
- A = 1, B = 2, C = 3, ..., Z = 26 (forward counting)
- Then she reverses: Y = 27, X = 28, ..., A = 51 (backward counting)
- This pattern continues indefinitely.

### Step 2: Determine the cycle length
The pattern consists of 50 characters:
- The first cycle goes from A (1) to Z (26) and then from Y (27) to A (51).
- After every 50 characters, the sequence starts again with A.

### Step 3: Find the closest multiple of 50 to 777
To find the character at the 777th position, we first find the closest multiple of 50 that is less than or equal to 777:
- The closest multiple of 50 to 777 is 750.

### Step 4: Identify the character at 750
Since 750 is a multiple of 50, it corresponds to the character A:
- 1st character = A
- 51st character = A
- 101st character = A
- ...
- 751st character = A

### Step 5: Count from 751 to 777
Now, we need to count from 751 to 777:
- 751 = A
- 752 = B
- 753 = C
- ...
- 776 = Z
- 777 = Y

### Conclusion
Thus, the character at the 777th position is **Y**.