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A shopkeeper charges sales tax of x%up t...

A shopkeeper charges sales tax of `x%`up to ₹2,000 and above it he charges `y%` A customer pays total tax of ₹320, when he purchases the goods worth ₹6,000 and he pay's the total tax of ₹680 for the goods worth ₹12,000. The value of (x-y) is :

A

0

B

`-2`

C

`-4`

D

5

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The correct Answer is:
To solve the problem, we need to find the values of \( x \) and \( y \) based on the information provided about the sales tax charged by the shopkeeper. ### Step-by-step Solution: 1. **Understanding the Tax Structure**: - The shopkeeper charges \( x\% \) sales tax on the first ₹2,000. - For any amount above ₹2,000, he charges \( y\% \). 2. **Calculating the Total Tax for ₹6,000**: - The first ₹2,000 incurs tax of \( x\% \): \[ \text{Tax on first } 2000 = \frac{x}{100} \times 2000 = 20x \] - The remaining amount is ₹4,000 (i.e., ₹6,000 - ₹2,000), which incurs tax of \( y\% \): \[ \text{Tax on remaining } 4000 = \frac{y}{100} \times 4000 = 40y \] - The total tax paid when purchasing goods worth ₹6,000 is given as ₹320: \[ 20x + 40y = 320 \quad \text{(Equation 1)} \] 3. **Calculating the Total Tax for ₹12,000**: - The first ₹2,000 incurs tax of \( x\% \): \[ \text{Tax on first } 2000 = 20x \] - The remaining amount is ₹10,000 (i.e., ₹12,000 - ₹2,000), which incurs tax of \( y\% \): \[ \text{Tax on remaining } 10000 = \frac{y}{100} \times 10000 = 100y \] - The total tax paid when purchasing goods worth ₹12,000 is given as ₹680: \[ 20x + 100y = 680 \quad \text{(Equation 2)} \] 4. **Solving the Equations**: - From Equation 1: \[ 20x + 40y = 320 \implies x + 2y = 16 \quad \text{(Divide by 20)} \] - From Equation 2: \[ 20x + 100y = 680 \implies x + 5y = 34 \quad \text{(Divide by 20)} \] 5. **Subtracting the Two Equations**: - We have: \[ x + 5y = 34 \quad \text{(Equation 3)} \] \[ x + 2y = 16 \quad \text{(Equation 4)} \] - Subtract Equation 4 from Equation 3: \[ (x + 5y) - (x + 2y) = 34 - 16 \] \[ 3y = 18 \implies y = 6 \] 6. **Finding \( x \)**: - Substitute \( y = 6 \) back into Equation 4: \[ x + 2(6) = 16 \implies x + 12 = 16 \implies x = 4 \] 7. **Finding \( x - y \)**: - Now, we calculate \( x - y \): \[ x - y = 4 - 6 = -2 \] ### Final Answer: The value of \( x - y \) is \( -2 \).
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