In an examination a candidate got `30%` marks and falled by 30 marks. If the passing marks are `60%` of the total marks, then the maximum marks will be:

Options

A. 450
B. 600
C. 300
D. 100

Answer

To solve the problem, let's break it down step by step.

### Step 1: Define Variables
Let the maximum marks be denoted as \( M \).

### Step 2: Calculate the Passing Marks
According to the problem, the passing marks are \( 60\% \) of the total marks. Therefore, the passing marks can be expressed as:
\[ \text{Passing Marks} = 0.6M \]

### Step 3: Calculate the Marks Obtained by the Candidate
The candidate obtained \( 30\% \) of the maximum marks. Thus, the marks obtained by the candidate are:
\[ \text{Marks Obtained} = 0.3M \]

### Step 4: Set Up the Equation
The candidate failed by \( 30 \) marks, which means the difference between the passing marks and the marks obtained is \( 30 \). We can set up the equation as follows:
\[ 0.6M - 0.3M = 30 \]

### Step 5: Simplify the Equation
Now, simplify the left side of the equation:
\[ 0.3M = 30 \]

### Step 6: Solve for Maximum Marks
To find \( M \), divide both sides by \( 0.3 \):
\[ M = \frac{30}{0.3} = 100 \]

### Conclusion
The maximum marks \( M \) are \( 100 \).