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In the Presidency College two candidates...

In the Presidency College two candidates contested a presidential election. `15%` of the voters did not vote amd 41 votes were invalid. The elected contestant got 314 votes more than the other candidate. If the elected candidate got `45%` of the total eligible voters, which is equal to the no of all the students of the college. The individual votes of each candidate are :

A

2250 and 1936

B

3568 and 3254

C

2442 and 2128

D

2457 and 2143

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To solve the problem step by step, we will break down the information given and use it to find the votes for each candidate. ### Step 1: Determine the total number of eligible voters Let the total number of eligible voters (students in the college) be \( V \). ### Step 2: Calculate the number of voters who actually voted Since 15% of the voters did not vote, the percentage of voters who did vote is: \[ 100\% - 15\% = 85\% \] Thus, the number of voters who actually voted is: \[ 0.85V \] ### Step 3: Account for invalid votes Out of the voters who voted, 41 votes were invalid. Therefore, the number of valid votes is: \[ \text{Valid votes} = 0.85V - 41 \] ### Step 4: Determine the votes received by the elected candidate We know that the elected candidate received 45% of the total eligible voters: \[ \text{Votes for elected candidate} = 0.45V \] ### Step 5: Determine the votes received by the other candidate Let the votes received by the other candidate be \( x \). According to the problem, the elected candidate received 314 votes more than the other candidate: \[ 0.45V = x + 314 \] ### Step 6: Set up the equation for valid votes The total number of valid votes can also be expressed as the sum of the votes received by both candidates: \[ 0.85V - 41 = 0.45V + x \] ### Step 7: Substitute for \( x \) in the valid votes equation From the equation \( 0.45V = x + 314 \), we can express \( x \) as: \[ x = 0.45V - 314 \] Now substitute this into the valid votes equation: \[ 0.85V - 41 = 0.45V + (0.45V - 314) \] ### Step 8: Simplify the equation Combine like terms: \[ 0.85V - 41 = 0.9V - 314 \] Rearranging gives: \[ 0.85V - 0.9V = -314 + 41 \] \[ -0.05V = -273 \] Thus, solving for \( V \): \[ V = \frac{273}{0.05} = 5460 \] ### Step 9: Calculate the votes for each candidate Now that we have \( V \), we can find the votes for each candidate: 1. Votes for the elected candidate: \[ \text{Votes for elected candidate} = 0.45 \times 5460 = 2457 \] 2. Votes for the other candidate using \( x \): \[ x = 0.45V - 314 = 2457 - 314 = 2143 \] ### Final Votes - Votes for the elected candidate: **2457** - Votes for the other candidate: **2143**
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