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When (x-a) is a factor of (x^3-3x^2a+2a^...

When (x-a) is a factor of `(x^3-3x^2a+2a^2x+p)` then find the value of p is:

A

0

B

1

C

2

D

3

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \( p \) such that \( (x - a) \) is a factor of the polynomial \( x^3 - 3x^2a + 2a^2x + p \). We can use the Factor Theorem, which states that if \( (x - a) \) is a factor of a polynomial \( f(x) \), then \( f(a) = 0 \). ### Step-by-step Solution: 1. **Define the polynomial**: Let \( f(x) = x^3 - 3x^2a + 2a^2x + p \). 2. **Apply the Factor Theorem**: Since \( (x - a) \) is a factor, we have: \[ f(a) = 0 \] 3. **Substitute \( a \) into the polynomial**: We calculate \( f(a) \): \[ f(a) = a^3 - 3a^2a + 2a^2a + p \] 4. **Simplify the expression**: Simplifying \( f(a) \): \[ f(a) = a^3 - 3a^3 + 2a^3 + p \] Combine like terms: \[ f(a) = (1 - 3 + 2)a^3 + p = 0 \] This simplifies to: \[ 0a^3 + p = 0 \] 5. **Solve for \( p \)**: From the equation \( 0 + p = 0 \), we find: \[ p = 0 \] ### Conclusion: Thus, the value of \( p \) is \( 0 \).
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