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The HCF of (x^4-1) and (x^3+x^2+x+1) is:...

The HCF of `(x^4-1)` and `(x^3+x^2+x+1)` is:

A

`(x^2-1)(x^2+1)`

B

`(x^2+1)(x+1)`

C

`(x+1)(x^2-1)`

D

`(x+1)(x^2+1)(x^3+1)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the HCF (Highest Common Factor) of the polynomials \( f(x) = x^4 - 1 \) and \( g(x) = x^3 + x^2 + x + 1 \), we can follow these steps: ### Step 1: Factor \( f(x) = x^4 - 1 \) We can recognize that \( x^4 - 1 \) can be factored using the difference of squares: \[ x^4 - 1 = (x^2 - 1)(x^2 + 1) \] Next, we can factor \( x^2 - 1 \) further since it is also a difference of squares: \[ x^2 - 1 = (x - 1)(x + 1) \] Thus, we can write: \[ f(x) = (x - 1)(x + 1)(x^2 + 1) \] ### Step 2: Factor \( g(x) = x^3 + x^2 + x + 1 \) We can factor \( g(x) \) by grouping: \[ g(x) = x^2(x + 1) + 1(x + 1) = (x + 1)(x^2 + 1) \] ### Step 3: Identify the common factors Now we have: - \( f(x) = (x - 1)(x + 1)(x^2 + 1) \) - \( g(x) = (x + 1)(x^2 + 1) \) The common factors between \( f(x) \) and \( g(x) \) are \( (x + 1) \) and \( (x^2 + 1) \). ### Step 4: Write the HCF Thus, the HCF of \( f(x) \) and \( g(x) \) is: \[ \text{HCF} = (x + 1)(x^2 + 1) \] ### Final Answer The HCF of \( x^4 - 1 \) and \( x^3 + x^2 + x + 1 \) is: \[ (x + 1)(x^2 + 1) \] ---
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