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Two parallel lines AB and CD are interse...

Two parallel lines AB and CD are intersected by a transversal EF at M and N respectively.
The lines MP and NP are the bisectors of interior angles `angle BMN` and `angle DNM` on the same side of the transversal. Then `angle MPN` is equal to :

A

`60^@`

B

`90^@`

C

`45^@`

D

`120^@`

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The correct Answer is:
To solve the problem, we need to find the measure of angle MPN given the conditions of the parallel lines and the angle bisectors. Here's a step-by-step solution: ### Step 1: Understand the Setup We have two parallel lines AB and CD intersected by a transversal EF at points M and N. The lines MP and NP are the angle bisectors of angles BMN and DNM, respectively. ### Step 2: Identify Angles Let: - Angle BMN = x - Angle DNM = y Since AB is parallel to CD, we know that: - Angle BMN + Angle DNM = 180° (because they are corresponding angles formed by the transversal EF). ### Step 3: Set Up the Equation From the above relationship, we can write: \[ x + y = 180° \] ### Step 4: Use the Angle Bisector Property Since MP is the bisector of angle BMN, it divides angle BMN into two equal parts: \[ \text{Angle BMP} = \frac{x}{2} \] \[ \text{Angle PMN} = \frac{x}{2} \] Similarly, since NP is the bisector of angle DNM: \[ \text{Angle DNP} = \frac{y}{2} \] \[ \text{Angle MNP} = \frac{y}{2} \] ### Step 5: Find Angle MPN Now, we need to find angle MPN. In triangle MPN, the sum of the angles is 180°: \[ \text{Angle MPN} + \text{Angle PMN} + \text{Angle MNP} = 180° \] Substituting the values we have: \[ \text{Angle MPN} + \frac{x}{2} + \frac{y}{2} = 180° \] ### Step 6: Simplify the Equation Now, we can simplify this equation: \[ \text{Angle MPN} + \frac{x + y}{2} = 180° \] Since we know from Step 3 that \( x + y = 180° \), we can substitute this into our equation: \[ \text{Angle MPN} + \frac{180°}{2} = 180° \] \[ \text{Angle MPN} + 90° = 180° \] ### Step 7: Solve for Angle MPN Now, solving for angle MPN: \[ \text{Angle MPN} = 180° - 90° = 90° \] Thus, the measure of angle MPN is: \[ \text{Angle MPN} = 90° \] ### Final Answer Angle MPN is equal to 90°. ---
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