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The bisector of the exterior angleA of D...

The bisector of the exterior `angleA` of `DeltaABC` intersects the side BC produced to D. Here CF is parallel to AD.

A

`(AB)/(AC)=(BD)/(CD)`

B

`(AB)/(AC)=(CD)/(BD)`

C

`(AB)/(AC)=(BC)/(CD)`

D

none of these

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A
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