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What is the ratio of inradius to the cir...

What is the ratio of inradius to the circumradius of a right angled triangle?

A

A) 2:3

B

B) `1:sqrt2`

C

C) 5:6

D

D) can't be determined

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The correct Answer is:
To find the ratio of the inradius (r) to the circumradius (R) of a right-angled triangle, we can follow these steps: ### Step 1: Understand the properties of a right-angled triangle In a right-angled triangle, the sides can be denoted as \( a \), \( b \), and \( c \), where \( c \) is the hypotenuse. The inradius \( r \) and circumradius \( R \) can be calculated using specific formulas. ### Step 2: Calculate the inradius (r) The formula for the inradius \( r \) of a triangle is given by: \[ r = \frac{A}{s} \] where \( A \) is the area of the triangle and \( s \) is the semi-perimeter. For a right-angled triangle: - The area \( A \) can be calculated as: \[ A = \frac{1}{2} \times a \times b \] - The semi-perimeter \( s \) is: \[ s = \frac{a + b + c}{2} \] ### Step 3: Calculate the circumradius (R) The circumradius \( R \) of a right-angled triangle can be calculated using the formula: \[ R = \frac{c}{2} \] where \( c \) is the length of the hypotenuse. ### Step 4: Find the ratio \( \frac{r}{R} \) Now that we have both \( r \) and \( R \), we can find the ratio: \[ \frac{r}{R} = \frac{\frac{A}{s}}{R} = \frac{\frac{\frac{1}{2} \times a \times b}{\frac{a + b + c}{2}}}{\frac{c}{2}} \] ### Step 5: Simplify the expression Substituting \( R \): \[ \frac{r}{R} = \frac{\frac{1}{2} \times a \times b}{\frac{a + b + c}{2} \times \frac{c}{2}} = \frac{a \times b}{(a + b + c) \times c} \] ### Step 6: Use the Pythagorean theorem Since \( c = \sqrt{a^2 + b^2} \), we can substitute this into our ratio: \[ \frac{r}{R} = \frac{a \times b}{(a + b + \sqrt{a^2 + b^2}) \times \sqrt{a^2 + b^2}} \] ### Conclusion The ratio of the inradius to the circumradius of a right-angled triangle simplifies to: \[ \frac{r}{R} = \frac{a \times b}{(a + b + \sqrt{a^2 + b^2}) \times \sqrt{a^2 + b^2}} \] ### Final Answer For a right-angled triangle, the ratio of the inradius to the circumradius is: \[ \frac{r}{R} = \frac{1}{2} \]
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