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In a regular polygon, if the number of d...

In a regular polygon, if the number of diagonals is k times the number of sides and each interior angle is `theta`, then k is:

A

`(3theta-2pi)/(2pi-2theta)`

B

`(4theta-pi)/(2pi-2theta)`

C

`(3theta-pi)/(2pi-2theta)`

D

`(3(theta-pi))/(2(pi-theta)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \( k \) in a regular polygon where the number of diagonals is \( k \) times the number of sides, and each interior angle is \( \theta \). ### Step-by-Step Solution: 1. **Understand the relationship between interior angle and sides**: The interior angle \( \theta \) of a regular polygon with \( n \) sides can be expressed as: \[ \theta = 180^\circ - \text{exterior angle} \] The exterior angle can be calculated as: \[ \text{exterior angle} = \frac{360^\circ}{n} \] Therefore, we can write: \[ \theta = 180^\circ - \frac{360^\circ}{n} \] 2. **Convert the angle to radians**: Since the problem uses \( \pi \), we convert the degrees to radians: \[ \theta = \pi - \frac{2\pi}{n} \] 3. **Rearranging to find \( n \)**: Rearranging the equation gives: \[ \frac{2\pi}{n} = \pi - \theta \] From this, we can solve for \( n \): \[ n = \frac{2\pi}{\pi - \theta} \] 4. **Formula for the number of diagonals**: The formula for the number of diagonals \( D \) in a polygon with \( n \) sides is: \[ D = \frac{n(n - 3)}{2} \] According to the problem, the number of diagonals is \( k \) times the number of sides: \[ D = k \cdot n \] 5. **Setting up the equation**: Substituting the formula for \( D \) into the equation gives: \[ \frac{n(n - 3)}{2} = k \cdot n \] We can cancel \( n \) (assuming \( n \neq 0 \)): \[ \frac{n - 3}{2} = k \] 6. **Substituting the value of \( n \)**: Now substitute \( n = \frac{2\pi}{\pi - \theta} \) into the equation for \( k \): \[ k = \frac{\frac{2\pi}{\pi - \theta} - 3}{2} \] 7. **Simplifying the expression**: Simplifying the expression for \( k \): \[ k = \frac{2\pi - 3(\pi - \theta)}{2(\pi - \theta)} \] This simplifies to: \[ k = \frac{2\pi - 3\pi + 3\theta}{2(\pi - \theta)} = \frac{3\theta - \pi}{2(\pi - \theta)} \] 8. **Final expression for \( k \)**: Thus, we arrive at the final expression: \[ k = \frac{3\theta - \pi}{2\pi - 2\theta} \] ### Conclusion: The value of \( k \) is: \[ k = \frac{3\theta - \pi}{2\pi - 2\theta} \]
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