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The distance between the centres of equa...

The distance between the centres of equal circles each of radius 3 cm is 10 cm. The length of a transverse tangent is:

A

4 cm

B

6 cm

C

8 cm

D

10 cm

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The correct Answer is:
To find the length of the transverse tangent between two equal circles, we can use the formula: \[ L = \sqrt{d^2 - (r_1 + r_2)^2} \] where: - \(L\) is the length of the transverse tangent, - \(d\) is the distance between the centers of the circles, - \(r_1\) and \(r_2\) are the radii of the circles. ### Step-by-Step Solution: 1. **Identify the values**: - The radius of each circle \(r_1 = r_2 = 3 \, \text{cm}\). - The distance between the centers of the circles \(d = 10 \, \text{cm}\). 2. **Calculate the sum of the radii**: \[ r_1 + r_2 = 3 + 3 = 6 \, \text{cm} \] 3. **Square the distance \(d\)**: \[ d^2 = 10^2 = 100 \] 4. **Square the sum of the radii**: \[ (r_1 + r_2)^2 = 6^2 = 36 \] 5. **Subtract the square of the sum of the radii from the square of the distance**: \[ d^2 - (r_1 + r_2)^2 = 100 - 36 = 64 \] 6. **Take the square root to find the length of the transverse tangent**: \[ L = \sqrt{64} = 8 \, \text{cm} \] ### Final Answer: The length of the transverse tangent is \(8 \, \text{cm}\). ---
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