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The sides of a triangle triangleABC are ...

The sides of a triangle `triangleABC` are 15 cm, 41 cm and 52 cm. Find the diameter of the circumcircle of the `triangleABC`

A

205/3 cm

B

208/3 cm

C

69 cm

D

70 cm

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The correct Answer is:
To find the diameter of the circumcircle of triangle ABC with sides 15 cm, 41 cm, and 52 cm, we will follow these steps: ### Step 1: Calculate the semi-perimeter (s) of the triangle. The semi-perimeter \( s \) is given by the formula: \[ s = \frac{a + b + c}{2} \] where \( a = 15 \), \( b = 41 \), and \( c = 52 \). Calculating \( s \): \[ s = \frac{15 + 41 + 52}{2} = \frac{108}{2} = 54 \text{ cm} \] ### Step 2: Calculate the area (A) of the triangle using Heron's formula. Heron's formula states: \[ A = \sqrt{s(s-a)(s-b)(s-c)} \] Substituting the values: \[ A = \sqrt{54(54-15)(54-41)(54-52)} \] Calculating each term: - \( s - a = 54 - 15 = 39 \) - \( s - b = 54 - 41 = 13 \) - \( s - c = 54 - 52 = 2 \) Now substituting these values back into the area formula: \[ A = \sqrt{54 \times 39 \times 13 \times 2} \] ### Step 3: Simplify the area calculation. Calculating the product: \[ 54 \times 39 = 2106 \] \[ 2106 \times 13 = 27378 \] \[ 27378 \times 2 = 54756 \] Now taking the square root: \[ A = \sqrt{54756} \] Calculating the square root gives: \[ A \approx 234 \text{ cm}^2 \] ### Step 4: Calculate the circumradius (R) using the formula. The circumradius \( R \) of a triangle can be calculated using the formula: \[ R = \frac{abc}{4A} \] Substituting the values: \[ R = \frac{15 \times 41 \times 52}{4 \times 234} \] Calculating the numerator: \[ 15 \times 41 = 615 \] \[ 615 \times 52 = 31980 \] Now calculating the denominator: \[ 4 \times 234 = 936 \] Now substituting these values back into the formula for \( R \): \[ R = \frac{31980}{936} \approx 34.2 \text{ cm} \] ### Step 5: Calculate the diameter (D) of the circumcircle. The diameter \( D \) is given by: \[ D = 2R \] Substituting the value of \( R \): \[ D = 2 \times 34.2 \approx 68.4 \text{ cm} \] ### Final Answer: The diameter of the circumcircle of triangle ABC is approximately **68.4 cm**. ---
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