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Two-third of a positive number and 16/21...

Two-third of a positive number and `16/216` of its reciprocal are equal. Find the positive number.

A

a. `9/25`

B

b. `14/4`

C

c. `4 /12`

D

d. `144/25`

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The correct Answer is:
To solve the problem step by step, we will follow the instructions given in the video transcript and derive the solution systematically. ### Step 1: Define the Variable Let the positive number be \( x \). ### Step 2: Set Up the Equation According to the problem, two-thirds of the positive number is equal to \( \frac{16}{216} \) of its reciprocal. The reciprocal of \( x \) is \( \frac{1}{x} \). Therefore, we can write the equation as: \[ \frac{2}{3} x = \frac{16}{216} \cdot \frac{1}{x} \] ### Step 3: Simplify the Right Side First, simplify \( \frac{16}{216} \): \[ \frac{16}{216} = \frac{16 \div 8}{216 \div 8} = \frac{2}{27} \] Now the equation becomes: \[ \frac{2}{3} x = \frac{2}{27} \cdot \frac{1}{x} \] ### Step 4: Cross-Multiply To eliminate the fractions, we can cross-multiply: \[ \frac{2}{3} x \cdot x = \frac{2}{27} \] This simplifies to: \[ \frac{2}{3} x^2 = \frac{2}{27} \] ### Step 5: Eliminate the Coefficient Next, we can multiply both sides by \( 3 \) to eliminate the fraction: \[ 2 x^2 = \frac{2 \cdot 3}{27} \] This simplifies to: \[ 2 x^2 = \frac{6}{27} \] ### Step 6: Further Simplify Now simplify \( \frac{6}{27} \): \[ \frac{6}{27} = \frac{6 \div 3}{27 \div 3} = \frac{2}{9} \] So we have: \[ 2 x^2 = \frac{2}{9} \] ### Step 7: Divide Both Sides by 2 Now, divide both sides by 2: \[ x^2 = \frac{2}{9} \div 2 = \frac{2}{9} \cdot \frac{1}{2} = \frac{1}{9} \] ### Step 8: Take the Square Root Finally, take the square root of both sides: \[ x = \sqrt{\frac{1}{9}} = \frac{1}{3} \] ### Step 9: Conclusion Thus, the positive number is: \[ \boxed{\frac{1}{3}} \]
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