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In DeltaABC angle B is 90^(@) and AD : B...

In `DeltaABC` angle B is `90^(@)` and AD : BD = 3 : 2 and CE : BE = 5 : 2 and AF : FC = 1 : 1 then find the area of `DeltaABC` where area of triangle `DeltaBDE` is equal to `20cm^(2)`

A

`40 cm^2`

B

`35 cm^2`

C

`52.5 cm^2`

D

none of the above

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The correct Answer is:
D
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