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The average temperature on Monday, Tuesd...

The average temperature on Monday, Tuesday and Wednesday was 41 °C and on Tuesday, Wednesday and Thursday it was 40 °C. If on Thursday it was exactly 39 °C, then on Monday, the temperature was

A

(a) 42 °C

B

(b) 46 °C

C

(c) 23 °C

D

(d) 26 °C

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The correct Answer is:
To solve the problem, we will use the information given about the average temperatures over the specified days. Let's break it down step by step. ### Step 1: Define the Variables Let: - \( M \) = Temperature on Monday - \( T \) = Temperature on Tuesday - \( W \) = Temperature on Wednesday - \( Th \) = Temperature on Thursday ### Step 2: Set Up the Equations From the problem, we have two average temperature equations: 1. The average temperature of Monday, Tuesday, and Wednesday is 41 °C: \[ \frac{M + T + W}{3} = 41 \] Multiplying both sides by 3 gives: \[ M + T + W = 123 \quad \text{(Equation 1)} \] 2. The average temperature of Tuesday, Wednesday, and Thursday is 40 °C: \[ \frac{T + W + Th}{3} = 40 \] Multiplying both sides by 3 gives: \[ T + W + Th = 120 \quad \text{(Equation 2)} \] ### Step 3: Substitute the Known Value We know from the problem that the temperature on Thursday \( Th \) is 39 °C. We can substitute this value into Equation 2: \[ T + W + 39 = 120 \] Subtracting 39 from both sides gives: \[ T + W = 81 \quad \text{(Equation 3)} \] ### Step 4: Substitute Equation 3 into Equation 1 Now, we can substitute Equation 3 into Equation 1: \[ M + (T + W) = 123 \] Substituting \( T + W = 81 \): \[ M + 81 = 123 \] Subtracting 81 from both sides gives: \[ M = 123 - 81 \] \[ M = 42 \] ### Conclusion The temperature on Monday was **42 °C**. ---
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