Alan purchased a phone for Rs. 5400 and a refrigerator for Rs. 9600. He sold the phone at 3/4th of its cost price and the refrigerator at 4/3rd of its cost price. What was the profit/loss ?

Options

A. a. 1580
B. b. 1750
C. c. 1850
D. d. 1870

Answer

To solve the problem, we need to calculate the selling price (SP) of both the phone and the refrigerator, then determine the total cost price (CP) and total selling price (SP) to find the overall profit or loss.

### Step-by-Step Solution:

1. **Calculate the Selling Price of the Phone:**
- Cost Price (CP) of the phone = Rs. 5400
- Selling Price (SP) of the phone = \( \frac{3}{4} \times \text{CP} \)
- SP of the phone = \( \frac{3}{4} \times 5400 = 4050 \)

2. **Calculate the Selling Price of the Refrigerator:**
- Cost Price (CP) of the refrigerator = Rs. 9600
- Selling Price (SP) of the refrigerator = \( \frac{4}{3} \times \text{CP} \)
- SP of the refrigerator = \( \frac{4}{3} \times 9600 = 12800 \)

3. **Calculate Total Cost Price:**
- Total CP = CP of phone + CP of refrigerator
- Total CP = 5400 + 9600 = 15000

4. **Calculate Total Selling Price:**
- Total SP = SP of phone + SP of refrigerator
- Total SP = 4050 + 12800 = 16850

5. **Calculate Profit or Loss:**
- Profit/Loss = Total SP - Total CP
- Profit/Loss = 16850 - 15000 = 1850

### Conclusion:
Alan made a profit of Rs. 1850.

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