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Given the. two roots .sqrt3 and -3sqrt3...

Given the. two roots .`sqrt3` and `-3sqrt3` how rnany quadratic equations can be formed?

A

2

B

1

C

0

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To determine how many quadratic equations can be formed given the roots \( \sqrt{3} \) and \( -3\sqrt{3} \), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Roots**: We are given two roots: - \( \alpha = \sqrt{3} \) - \( \beta = -3\sqrt{3} \) 2. **Use the Quadratic Equation Formula**: The standard form of a quadratic equation with roots \( \alpha \) and \( \beta \) is given by: \[ x^2 - (\alpha + \beta)x + \alpha \beta = 0 \] 3. **Calculate the Sum of the Roots**: Find \( \alpha + \beta \): \[ \alpha + \beta = \sqrt{3} + (-3\sqrt{3}) = \sqrt{3} - 3\sqrt{3} = -2\sqrt{3} \] 4. **Calculate the Product of the Roots**: Find \( \alpha \beta \): \[ \alpha \beta = \sqrt{3} \times (-3\sqrt{3}) = -3 \times 3 = -9 \] 5. **Substitute into the Quadratic Formula**: Substitute the values of the sum and product into the quadratic equation: \[ x^2 - (-2\sqrt{3})x + (-9) = 0 \] This simplifies to: \[ x^2 + 2\sqrt{3}x - 9 = 0 \] 6. **Conclusion**: Since we have only one set of roots, we can form only one quadratic equation from these roots. ### Final Answer: Only one quadratic equation can be formed with the given roots \( \sqrt{3} \) and \( -3\sqrt{3} \). ---
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