If a= 1+ log(x) yz, b=1 + log(y)zx and c...

If `a= 1+ log_(x) yz, b=1 + log_(y)zx` and c=1 `+log_(z)xy`, the ab+bc +ca is:

A

1

B

0

C

abc

D

none of these

Verified by Experts

The correct Answer is:

C

Similar Questions

Explore conceptually related problems

If a = 1 + "log"_(x) yz, b = 1 + "log"_(y) zx, c =1 + "log"_(z) xy, then ab+bc+ca =

If x = 1 + log_(a) bc, y = 1 + log_(b) ca, z = 1 + log_(c) ab, then xy + yz + zx =

If a=log_(x)(yz),b=log_(y)(zx),c=log_(z)(xy) where x,y,z are positive reals not equal to unity,then abc-a-b-c is equal to

If p = log_(a) bc, q = log_(b) ca and r = log_(c ) ab , then which of the following is true ?

If x = log_(a) bc, y = log_(b) ca, z = log_(c) ab, then the value of (1)/(1 + x) + (1)/(1 + y) + (1)/(l + z) will be

If x=1+log_(a) bc, y=1+log_(b) ca, z=1+log_(c) ab , then (xyz)/(xy+yz+zx) is equal to

If x=log_(a)bc, y=log_(b)ac and z=log_(c)ab then which of the following is equal to unity ?

If x = log_(c) b + log_(b) c, y = log_(a) c + log_(c) a, z = log_(b) a + log_(a) b, then x^(2) + y^(2) + z^(2) - 4 =