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The sum of n terms of the series 1^2 ...

The sum of n terms of the series
`1^2 + (1^2 + 3^2) + (1^2 + 3^2 + 5^2) + …` is :

A

`1/3 (n^3+n^2+1)`

B

`1/6 n(n+1)(2n^2+2n-1)`

C

`1/3 (2n^2+2n-1)`

D

none

Text Solution

Verified by Experts

The correct Answer is:
B
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