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1^k + 2^k + 3^k + … + n^k is divisble by...

`1^k + 2^k + 3^k + … + n^k` is divisble by 1 + 2 +3 + … n for every n` in N`, then K is :

A

even

B

odd

C

only prime

D

none

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The correct Answer is:
B
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QUANTUM CAT-SEQUENCE, SERIES & PROGRESSIONS-QUESTION BANK
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  14. What is the sum of n terms of the series -1 + 1^2 - 2 + 2^2 - 3 + 3^2 ...

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  15. Find the sum of 1+2/3+4/9+6/27+8/81+10/243+....+oo:

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  16. Sum of n terms of the series loga + log((a^2)/(b)) + log((a^3)/(b^2...

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  17. If a1 , a2 , a3, …."" an are in A.P. where ai gt 0 for all i , then th...

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  18. If log2,log(2^x-1)a n dlog2log(2^x+3) are in A.P., write the value of ...

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