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Find the equation of the line which pass...

Find the equation of the line which passes through the point of intersection of the lines 2x-y+5=0 and 5x+3y-4 =0 and is perpendicular to the line x-3y+21 =0

A

2x + y + 8 = 0

B

3x + 4y - 7 = 0

C

3x + y = 0

D

none of these

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • The equation of the line passing through the point of intersection of the lines x-3y+2=0 and 2x+5y-7=0 and perpendicular to the line 3x+2y+5=0, is

    A
    2x-3y+1=0
    B
    6x-9y+11=0
    C
    2x-3y+5=0
    D
    3x-2y+1=0

  • Find the equation of the line which passes through the point of intersection of the lines x+2y-3=0 and 4x-y+7=0 and is parallel to the line y-x+10 =0 .

    A
    2x+2y +5=0
    B
    3x-3y=10
    C
    3x+2y-8=0
    D
    none of these

  • Find the equation of the line which passes through the point of intersection of the lines x + 2y - 3 = 0 and 4x - y + 7 = 0 and is parallel to the line y - x + 10 = 0.

    A
    2x + 2y + 5 = 0
    B
    3x - 3y + 10 = 0
    C
    3x + 2y - 8 = 0
    D
    none of these

    • Similar Questions

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