Select the odd one out and justify your choice:
`NaOH,CH_(3)COOH,C_(2)H_(5)OH,HCl`

Explanation

To solve the problem of selecting the odd one out from the list of compounds: NaOH, CH₃COOH, C₂H₅OH, and HCl, we can analyze each compound based on its chemical properties.

### Step-by-Step Solution:

1. **Identify the nature of each compound:**
- **NaOH (Sodium Hydroxide):** This is a strong base. When dissolved in water, it dissociates into Na⁺ and OH⁻ ions.
- **CH₃COOH (Acetic Acid):** This is a weak acid. In solution, it partially dissociates into CH₃COO⁻ (acetate ion) and H⁺ ions.
- **C₂H₅OH (Ethanol):** This is an alcohol and is neither an acid nor a base. It does not dissociate to produce H⁺ or OH⁻ ions in solution.
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