Select the odd one out and justify your choice:
`NaOH,KCl,NaHCO_(3),Na_(2)CO_(3)`

Explanation

To solve the question of selecting the odd one out from the list: NaOH, KCl, NaHCO3, and Na2CO3, we can analyze each compound based on their chemical properties.

### Step-by-Step Solution:

1. **Identify the nature of each compound:**
- **NaOH (Sodium Hydroxide):** This is a strong base. When dissolved in water, it dissociates completely to produce hydroxide ions (OH⁻).
- **KCl (Potassium Chloride):** This is a neutral salt formed from the reaction of a strong acid (HCl) and a strong base (KOH). It does not exhibit acidic or basic properties in solution.
- **NaHCO3 (Sodium Bicarbonate):** This is a salt that is slightly basic in nature. It is formed from a strong base (NaOH) and a weak acid (H2CO3, carbonic acid).
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