Three different elctrolytic cells A, B and C are connected in separate circuits .Electrolytic cell A contains sodium chloride solution. When the circuit is complete . A bulb in the circuit glows brightly .electrolytic cell B contains acetic acid solution and in this case the bulb in the circuit glows dimly . The elctrolytic cell C contains sugar solution and the bulb does not glow . Give a reason for each of these observations .

Explanation

To answer the question regarding the observations in the three electrolytic cells A, B, and C, we will analyze each cell based on the type of electrolyte present and its ability to conduct electricity.

### Step-by-Step Solution:

1. **Electrolytic Cell A (Sodium Chloride Solution)**:
- Sodium chloride (NaCl) is a strong electrolyte. This means that when it is dissolved in water, it completely dissociates into its ions: Na⁺ (sodium ions) and Cl⁻ (chloride ions).
- The presence of a large number of ions allows for efficient conduction of electricity. As a result, when the circuit is completed, the ions move towards the electrodes (Na⁺ towards the cathode and Cl⁻ towards the anode), allowing a significant current to flow.
- **Observation**: The bulb glows brightly because of the high conductivity of the solution due to the complete dissociation of NaCl.
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