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Evaluate : 5x^(3)y^(4) when x=2 ,y=-1...

Evaluate :
`5x^(3)y^(4) ` when x=2 ,y=-1

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The correct Answer is:
To evaluate the expression \( 5x^3y^4 \) when \( x = 2 \) and \( y = -1 \), we will follow these steps: ### Step 1: Substitute the values of \( x \) and \( y \) We start by substituting the given values into the expression: \[ 5x^3y^4 = 5(2)^3(-1)^4 \] ### Step 2: Calculate \( x^3 \) and \( y^4 \) Next, we calculate \( (2)^3 \) and \( (-1)^4 \): \[ (2)^3 = 2 \times 2 \times 2 = 8 \] \[ (-1)^4 = (-1) \times (-1) \times (-1) \times (-1) = 1 \] (Note: Since the negative number is raised to an even power, the result is positive.) ### Step 3: Substitute back into the expression Now, we substitute these results back into the expression: \[ 5(2)^3(-1)^4 = 5 \times 8 \times 1 \] ### Step 4: Multiply the numbers Finally, we perform the multiplication: \[ 5 \times 8 \times 1 = 40 \] ### Final Answer Thus, the value of the expression \( 5x^3y^4 \) when \( x = 2 \) and \( y = -1 \) is: \[ \boxed{40} \]
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