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A hollow sphere of internal and external diameters 4 cm and 8 cm respectively is melted to form a solid cylinder of base diameter 8 cm. The height of the cylinder is approximately :

A

4.5 cm

B

4.57 cm

C

4.67 cm

D

4.7 cm

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The correct Answer is:
To solve the problem, we need to find the height of a solid cylinder formed by melting a hollow sphere. Let's break it down step by step. ### Step 1: Identify the given dimensions - Internal diameter of the hollow sphere = 4 cm - External diameter of the hollow sphere = 8 cm ### Step 2: Calculate the radii - Internal radius (r) = Internal diameter / 2 = 4 cm / 2 = 2 cm - External radius (R) = External diameter / 2 = 8 cm / 2 = 4 cm ### Step 3: Calculate the volume of the hollow sphere The volume of the hollow sphere is given by the formula: \[ \text{Volume} = \frac{4}{3} \pi (R^3 - r^3) \] Substituting the values of R and r: \[ \text{Volume} = \frac{4}{3} \pi (4^3 - 2^3) \] Calculating the cubes: \[ = \frac{4}{3} \pi (64 - 8) = \frac{4}{3} \pi (56) \] ### Step 4: Calculate the volume of the cylinder The volume of the cylinder is given by the formula: \[ \text{Volume} = \pi r^2 h \] Where r is the radius of the cylinder's base. Since the diameter of the cylinder is also 8 cm, the radius is: \[ r = \frac{8}{2} = 4 \text{ cm} \] Thus, the volume of the cylinder can be expressed as: \[ \text{Volume} = \pi (4^2) h = \pi (16) h \] ### Step 5: Set the volumes equal to each other Since the hollow sphere is melted to form the cylinder, their volumes are equal: \[ \frac{4}{3} \pi (56) = \pi (16) h \] ### Step 6: Cancel out \(\pi\) from both sides \[ \frac{4}{3} (56) = 16h \] ### Step 7: Solve for h First, calculate the left side: \[ \frac{4 \times 56}{3} = \frac{224}{3} \] Now, set it equal to \(16h\): \[ \frac{224}{3} = 16h \] Now, isolate h: \[ h = \frac{224}{3 \times 16} \] Calculating \(3 \times 16 = 48\): \[ h = \frac{224}{48} \] Now simplify: \[ h = \frac{224 \div 16}{48 \div 16} = \frac{14}{3} \approx 4.67 \text{ cm} \] ### Final Answer The height of the cylinder is approximately \(4.67 \text{ cm}\). ---
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