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The perimeter of a parallelogram with on...

The perimeter of a parallelogram with one internal angle `150^@` in 64 cm. Find the length of its sides when its area is maximum.

A

16, 16

B

15, 17

C

14, 18

D

can't be determined

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The correct Answer is:
To find the lengths of the sides of a parallelogram with a perimeter of 64 cm and one internal angle of 150° when its area is maximized, we can follow these steps: ### Step 1: Understand the properties of the parallelogram A parallelogram has opposite sides that are equal in length. Let's denote the lengths of the sides as \( a \) and \( b \). ### Step 2: Write the equation for the perimeter The perimeter \( P \) of a parallelogram is given by the formula: \[ P = 2(a + b) \] Given that the perimeter is 64 cm, we can set up the equation: \[ 2(a + b) = 64 \] Dividing both sides by 2 gives: \[ a + b = 32 \quad \text{(Equation 1)} \] ### Step 3: Write the formula for the area The area \( A \) of a parallelogram can be calculated using the formula: \[ A = a \cdot b \cdot \sin(\theta) \] where \( \theta \) is the angle between sides \( a \) and \( b \). Here, \( \theta = 150^\circ \). ### Step 4: Calculate \( \sin(150^\circ) \) We know that: \[ \sin(150^\circ) = \sin(180^\circ - 30^\circ) = \sin(30^\circ) = \frac{1}{2} \] Thus, the area becomes: \[ A = a \cdot b \cdot \frac{1}{2} = \frac{1}{2} ab \quad \text{(Equation 2)} \] ### Step 5: Substitute \( b \) from Equation 1 into Equation 2 From Equation 1, we can express \( b \) in terms of \( a \): \[ b = 32 - a \] Substituting this into the area formula gives: \[ A = \frac{1}{2} a (32 - a) = \frac{1}{2} (32a - a^2) \] ### Step 6: Maximize the area To maximize the area, we can differentiate \( A \) with respect to \( a \) and set the derivative to zero: \[ A = \frac{1}{2} (32a - a^2) \] Taking the derivative: \[ \frac{dA}{da} = \frac{1}{2} (32 - 2a) \] Setting the derivative equal to zero: \[ 32 - 2a = 0 \implies 2a = 32 \implies a = 16 \] ### Step 7: Find \( b \) Using \( a = 16 \) in Equation 1: \[ b = 32 - a = 32 - 16 = 16 \] ### Conclusion Thus, the lengths of the sides of the parallelogram when the area is maximized are: \[ a = 16 \, \text{cm}, \, b = 16 \, \text{cm} \]
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