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The domain of the function f(x)=logx^2 i...

The domain of the function f(x)=`logx^2` is :

A

R

B

`R^+`

C

R-{0}

D

`R^+cup{0}`

Text Solution

AI Generated Solution

The correct Answer is:
To find the domain of the function \( f(x) = \log(x^2) \), we need to determine the values of \( x \) for which the function is defined. The logarithmic function is defined under certain conditions. ### Step-by-step Solution: 1. **Identify the logarithmic function**: The function given is \( f(x) = \log(x^2) \). 2. **Understand the conditions for the logarithm**: The logarithm \( \log_b(a) \) is defined when: - \( a > 0 \) (the argument of the logarithm must be positive) - \( b > 0 \) (the base of the logarithm must be positive) - \( b \neq 1 \) (the base cannot be 1) In this case, we are considering \( \log(x^2) \) where the base is assumed to be 10 (or any valid base greater than 0 and not equal to 1). 3. **Set the argument greater than zero**: For the function \( \log(x^2) \) to be defined, we need: \[ x^2 > 0 \] 4. **Solve the inequality**: The expression \( x^2 > 0 \) is true for all real numbers \( x \) except when \( x = 0 \). Thus, the only value that makes \( x^2 \) equal to zero is \( x = 0 \). 5. **Determine the domain**: Therefore, the domain of the function \( f(x) = \log(x^2) \) is all real numbers except \( x = 0 \). In interval notation, this can be expressed as: \[ (-\infty, 0) \cup (0, \infty) \] ### Final Answer: The domain of the function \( f(x) = \log(x^2) \) is \( \mathbb{R} \setminus \{0\} \) or in interval notation, \( (-\infty, 0) \cup (0, \infty) \). ---
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