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a"@"b=|a-b| a**b=ab a#b=|a^(2)-b^(2)...

`a"@"b=|a-b|`
`a**b=ab`
`a#b=|a^(2)-b^(2)|`
`aDeltab=a^(2)+b^(2)`
where `a, b in R and a neb` and the real algebraic operations are unchanged.
The value of the expression `[(a#b)div(a"@"b)]^(2)-2(a**b):`

A

a#b

B

`aDeltab`

C

(a#b)(a@b)

D

can't be determined

Text Solution

Verified by Experts

The correct Answer is:
B
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