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A car moving at a speed of 75 km/hr cove...

A car moving at a speed of 75 km/hr covers certain distance in 2 hours. If its speed is reduced by 15 km/hr, in what time it will cover the same distance?

A

155 minutes

B

150 minutes

C

140 minutes

D

135 minutes

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AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these calculations: ### Step 1: Calculate the distance covered by the car at the initial speed. Given: - Speed (S1) = 75 km/hr - Time (t1) = 2 hours Using the formula for distance: \[ \text{Distance} (d) = \text{Speed} \times \text{Time} \] \[ d = S1 \times t1 = 75 \, \text{km/hr} \times 2 \, \text{hr} = 150 \, \text{km} \] ### Step 2: Determine the new speed after reduction. The speed is reduced by 15 km/hr: \[ \text{New Speed} (S2) = S1 - 15 = 75 \, \text{km/hr} - 15 \, \text{km/hr} = 60 \, \text{km/hr} \] ### Step 3: Calculate the time taken to cover the same distance at the new speed. Using the formula for time: \[ \text{Time} (t2) = \frac{\text{Distance}}{\text{Speed}} \] \[ t2 = \frac{d}{S2} = \frac{150 \, \text{km}}{60 \, \text{km/hr}} \] ### Step 4: Simplify the calculation for time. \[ t2 = \frac{150}{60} = 2.5 \, \text{hours} \] ### Step 5: Convert the time from hours to minutes. Since the options are given in minutes, we convert hours to minutes: \[ t2 \text{ (in minutes)} = t2 \text{ (in hours)} \times 60 \] \[ t2 = 2.5 \, \text{hours} \times 60 = 150 \, \text{minutes} \] ### Final Answer: The time taken to cover the same distance at the reduced speed of 60 km/hr is **150 minutes**. ---
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