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In how many ways can 5 men and 2 ladies ...

In how many ways can 5 men and 2 ladies be arranged at a round table if two ladies are never together?

A

5040

B

480

C

240

D

720

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of arranging 5 men and 2 ladies at a round table such that the two ladies are never seated next to each other, we can follow these steps: ### Step-by-Step Solution: 1. **Arrange the Men:** - Since the arrangement is circular, we can fix one man to eliminate the effect of rotation. Therefore, we arrange the remaining 4 men around him. - The number of ways to arrange 5 men in a circular manner is given by \((n-1)!\), where \(n\) is the number of men. - Thus, the number of arrangements for the men is: \[ 4! = 24 \] 2. **Identify Gaps for Ladies:** - After arranging the 5 men, they create gaps where the ladies can be seated. In a circular arrangement of 5 men, there are 5 gaps (one between each pair of men). - These gaps can be visualized as follows: - Gap 1 (between Man 1 and Man 2) - Gap 2 (between Man 2 and Man 3) - Gap 3 (between Man 3 and Man 4) - Gap 4 (between Man 4 and Man 5) - Gap 5 (between Man 5 and Man 1) 3. **Choose Gaps for the Ladies:** - We need to select 2 out of these 5 gaps to place the ladies. The number of ways to choose 2 gaps from 5 is given by the combination formula \(\binom{n}{r}\), where \(n\) is the total number of gaps and \(r\) is the number of gaps to choose. - Therefore, the number of ways to choose 2 gaps from 5 is: \[ \binom{5}{2} = 10 \] 4. **Arrange the Ladies:** - The two ladies can be arranged in the selected gaps in \(2!\) ways (since there are 2 ladies). - Thus, the number of arrangements for the ladies is: \[ 2! = 2 \] 5. **Calculate the Total Arrangements:** - Now, we multiply the number of arrangements of the men, the ways to choose the gaps, and the arrangements of the ladies: \[ \text{Total arrangements} = 4! \times \binom{5}{2} \times 2! = 24 \times 10 \times 2 \] - Calculating this gives: \[ 24 \times 10 = 240 \] \[ 240 \times 2 = 480 \] ### Final Answer: The total number of ways to arrange 5 men and 2 ladies at a round table such that the two ladies are never seated next to each other is **480**.
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