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The population of a town is increased fr...

The population of a town is increased from 54500 to 58500 in one year. What is the percentage increase in the population?

A

4.34%

B

7.34%

C

5.34%

D

6.34%

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AI Generated Solution

The correct Answer is:
To find the percentage increase in the population of the town, we can follow these steps: ### Step 1: Determine the Initial and Final Population - The initial population (P1) is 54,500. - The final population (P2) is 58,500. ### Step 2: Calculate the Increase in Population - The increase in population can be calculated by subtracting the initial population from the final population: \[ \text{Increase} = P2 - P1 = 58,500 - 54,500 = 4,000 \] ### Step 3: Calculate the Percentage Increase - The percentage increase is calculated using the formula: \[ \text{Percentage Increase} = \left( \frac{\text{Increase}}{\text{Initial Population}} \right) \times 100 \] - Substituting the values we have: \[ \text{Percentage Increase} = \left( \frac{4,000}{54,500} \right) \times 100 \] ### Step 4: Perform the Calculation - First, calculate the fraction: \[ \frac{4,000}{54,500} \approx 0.07339 \] - Now, multiply by 100 to convert it to a percentage: \[ 0.07339 \times 100 \approx 7.339\% \] ### Step 5: Round Off the Result - Rounding off 7.339% gives us approximately 7.34%. ### Final Answer - The percentage increase in the population is approximately **7.34%**. ---
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