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Solve the following problems independent...

Solve the following problems independently of each other
Rollmall is a fast food outlet, which delivers the veg and non-veg rolls in its vicinity. Bawarchi is an employee, who is assigned to pack the rolls in the boxes for delivery. He has 5 rolls in hand to pack in the 3 boxes so that none of the boxes remains empty.
Find the number of ways of packing the rolls, if each roll is identical but each box is distinct.

A

3

B

5

C

6

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of packing 5 identical rolls into 3 distinct boxes such that none of the boxes remains empty, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Problem**: We have 5 identical rolls and 3 distinct boxes. The requirement is that each box must contain at least one roll. 2. **Initial Distribution**: Since each box must contain at least one roll, we can start by placing one roll in each of the 3 boxes. This ensures that no box is empty. - After placing 1 roll in each of the 3 boxes, we have used 3 rolls. - Remaining rolls = 5 - 3 = 2 rolls. 3. **Distributing Remaining Rolls**: Now we need to distribute the remaining 2 rolls into the 3 boxes. Since the rolls are identical, we can use the "stars and bars" theorem to find the number of ways to distribute these rolls. 4. **Applying the Stars and Bars Theorem**: The formula for distributing \( n \) identical items (rolls) into \( r \) distinct groups (boxes) is given by: \[ \text{Number of ways} = \binom{n + r - 1}{r - 1} \] Here, \( n \) is the number of remaining rolls (2), and \( r \) is the number of boxes (3). 5. **Substituting Values**: We substitute \( n = 2 \) and \( r = 3 \) into the formula: \[ \text{Number of ways} = \binom{2 + 3 - 1}{3 - 1} = \binom{4}{2} \] 6. **Calculating the Binomial Coefficient**: Now we calculate \( \binom{4}{2} \): \[ \binom{4}{2} = \frac{4!}{2!(4-2)!} = \frac{4 \times 3}{2 \times 1} = 6 \] 7. **Conclusion**: Therefore, the number of ways to pack the rolls into the boxes such that none of the boxes is empty is **6**. ### Final Answer: The number of ways of packing the rolls is **6**. ---
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