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Sarvesh wants to prepare a bouquet with ...

Sarvesh wants to prepare a bouquet with roses, lilies, orchids and carnations, so he walked inyo a large garden of flowers. In how many ways can he prepare a bouquet of 15 flowers such that he selects at least 1 rose, 2 lilies, 3 orchids and 4 carnations for his bouquet?

A

A) 24

B

B) 120

C

C) 56

D

D) 112

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AI Generated Solution

The correct Answer is:
To solve the problem of how many ways Sarvesh can prepare a bouquet of 15 flowers with the given constraints, we can break down the solution step by step. ### Step-by-Step Solution: 1. **Identify the Minimum Requirements**: Sarvesh must select at least: - 1 rose - 2 lilies - 3 orchids - 4 carnations Adding these minimum requirements gives us: \[ 1 + 2 + 3 + 4 = 10 \text{ flowers} \] 2. **Calculate Remaining Flowers**: Since Sarvesh wants a total of 15 flowers, we can find the remaining number of flowers he can choose after fulfilling the minimum requirements: \[ 15 - 10 = 5 \text{ flowers} \] 3. **Define the Variables**: Let: - \( r \) = number of additional roses (beyond the 1 required) - \( l \) = number of additional lilies (beyond the 2 required) - \( o \) = number of additional orchids (beyond the 3 required) - \( c \) = number of additional carnations (beyond the 4 required) The equation representing the total number of additional flowers can be expressed as: \[ r + l + o + c = 5 \] 4. **Use the Stars and Bars Theorem**: To find the number of non-negative integer solutions to the equation \( r + l + o + c = 5 \), we can use the stars and bars combinatorial method. The formula for the number of solutions is given by: \[ \binom{n + k - 1}{k - 1} \] where \( n \) is the total number of items to distribute (5 flowers), and \( k \) is the number of categories (4 types of flowers). Here, \( n = 5 \) and \( k = 4 \): \[ \text{Number of ways} = \binom{5 + 4 - 1}{4 - 1} = \binom{8}{3} \] 5. **Calculate the Combination**: Now, we calculate \( \binom{8}{3} \): \[ \binom{8}{3} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = \frac{336}{6} = 56 \] 6. **Conclusion**: Therefore, the total number of ways Sarvesh can prepare his bouquet of 15 flowers, while satisfying the given conditions, is: \[ \boxed{56} \]
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