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Find the total number of non-negative in...

Find the total number of non-negative integers less than 1000 for which the sum of the digits is 10

A

A) 63

B

B) 66

C

C) 67

D

B) 56

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The correct Answer is:
To solve the problem of finding the total number of non-negative integers less than 1000 for which the sum of the digits is 10, we can break down the solution step by step. ### Step 1: Define the variables We denote the three digits of a number as \(X\), \(Y\), and \(Z\). The requirement is that the sum of these digits must equal 10: \[ X + Y + Z = 10 \] where \(X\), \(Y\), and \(Z\) are the digits of the number. ### Step 2: Set up the equation for non-negative integer solutions We need to find the non-negative integer solutions to the equation \(X + Y + Z = 10\). This can be solved using the "stars and bars" theorem, which states that the number of non-negative integer solutions to the equation \(x_1 + x_2 + ... + x_r = n\) is given by: \[ \binom{n + r - 1}{r - 1} \] In our case, \(n = 10\) (the sum) and \(r = 3\) (the number of digits). ### Step 3: Apply the formula Substituting the values into the formula, we have: \[ \text{Number of solutions} = \binom{10 + 3 - 1}{3 - 1} = \binom{12}{2} \] ### Step 4: Calculate \(\binom{12}{2}\) Now we calculate \(\binom{12}{2}\): \[ \binom{12}{2} = \frac{12 \times 11}{2 \times 1} = \frac{132}{2} = 66 \] So, there are 66 non-negative integer solutions to the equation \(X + Y + Z = 10\). ### Step 5: Exclude invalid cases Next, we need to exclude cases where any of the digits \(X\), \(Y\), or \(Z\) are greater than 9, as they cannot be valid single-digit numbers. The only way this can happen is if one of the digits is equal to 10. The possible cases to exclude are: 1. \(X = 10, Y = 0, Z = 0\) 2. \(X = 0, Y = 10, Z = 0\) 3. \(X = 0, Y = 0, Z = 10\) These three cases are invalid because they exceed the digit limit of 9. ### Step 6: Calculate the valid solutions Thus, we subtract these invalid cases from the total: \[ \text{Valid solutions} = 66 - 3 = 63 \] ### Final Answer Therefore, the total number of non-negative integers less than 1000 for which the sum of the digits is 10 is: \[ \boxed{63} \]
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