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Prove that : |veca + vecb|le|veca|+|vecb...

Prove that : `|veca + vecb|le|veca|+|vecb|`.

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|veca| = |vecb| = veca = vecb .

Prove that veca xx (vecb xx vecc) + vecb xx (vecc xx veca) + vecc xx (veca xx vecb) = vec0 and hence prove that veca xx (vecb xx vecc), vecb xx (vecc xx veca), vecc xx (veca xx vecb) are coplanar.

State when the equality will hold, |veca - vecb|ge|veca|-|vecb|

If two vectors veca and vecb are such that |veca| = 3, |vecb| = 2 and veca.vecb = 6, find |veca+vecb| and |veca-vecb| .

Prove that (veca.vecb)^2=a^2b^2-(veca xx vecb)^2

Prove that |veca xx vecb|^(2) = abs(veca)^(2)abs(vecb)^(2) - (veca * vecb)^(2)

Vectors veca,vecb, vecc are such that veca + vecb + vecc = 0 and |veca| = 3, |vecb| = 5 and |vecc]= 7 . Find the angle between veca and vecb .

What is geometrical significance of the relation |veca+vecb| = |veca-vecb|

If veca,vecb and vecc are three vectors such that veca x vecb = vecc and vecb x vecc = veca , then prove that veca,vecb and vecc are mutually at right angles and |vecb| = 1,|vecc| = |veca|

For any three vectors veca,vecb,vecc show that [(veca-vecb) (vecc-veca) (vecb-vecc)] = 0

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  3. Prove that : |veca + vecb|le|veca|+|vecb|.

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