In YDSE, having slits of equal width, let `beta` be the fringe width and `I_(0)` be the maximum intensity. At a distance x from the central brigth fringe, the intensity will be

In YDSE of equal width slits, if intensity at the center of screen is I_(0) , then intensity at a distance of beta // 4 from the central maxima is

In YDSE of equal width slits, if intensity at the center of screen is I_(0) , then intensity at a distance of beta // 4 from the central maxima is

In Young's double slit experiment of central fringe is I_(0) and fringe width is beta . If a point is at a distance x from the central fringe, then the intensity at that point is

In a double slit experiment, the separation between the slits is d = 0.25 cm and the distance of the screen D = 100 cm from the slits. If the wavelength of light used is lambda = 6000 Å and I_(0) is the intensity of the central bright fringe, the intensity at a distance x =4xx10^(-5)m from the central maximum is

In YDSE, when separation between two slits is increased, fringe width

In a double slit experiment ,the separation between the slits is d=0.25cm and the distance of the screen D=100 cm from the slits .if the wavelength of light used in lambda=6000Å and I_(0) is the intensity of the central bright fringe. The intensity at a distance x=4xx10^(-5) in form the central maximum is-

In a double slit experiment ,the separation between the slits is d=0.25cm and the distance of the screen D=100 cm from the slits .if the wavelength of light used in lambda=6000Å and I_(0) is the intensity of the central bright fringe.the intensity at a distance x=4xx10^(-5) in form the central maximum is-

Fringe width equal to 1 mm is observed in the interference pattern of biprism experiment. Then the distance of nearest bright fringe from the central bright fringe will be :